You visited us 1 times! Enjoying our articles? Unlock Full Access!

Le Chatelier's Principle for Del N Equals to 0

If 100 mole o...

Question

If 100 mole of $H_{2} O_{2}$ decompose at $1$ bar and $300$ K, then what will be the work done(kJ) by one mole of $O_{2} (g)$ as it expands against $1$ bar pressure?
$2 H_{2} O_{2} (I) ⇋ 2 H_{2} O (l) + O_{2} (g)$

Open in App

Solution

$2 H_{2} O_{2} (l) ⇌ 2 H_{2} O (l) + O_{2} (g)$
$W = - P_{e x t} . Δ V$ $n_{O_{2}} =$ moles of $O_{2} = 50$ moles
$= - (n_{O_{2}} R T)$ $100$ mol of $H_{2} O_{2}$ gives $50$ moles of $O_{2}$ .
$= - 50 \times 8.3 \times 300$
$= - 124.5 k J$
Work done by $O_{2} (g) = 124.5 k J$

Suggest Corrections

Similar questions

100

H_{2} O_{2}

1

300 K

(k J)

O_{2} (g)

1

2 H_{2} O_{2} (l) ⇌ 2 H_{2} O (l) + O_{2} (g)

(R = 8.3 J K^{- 1} {m o l}^{- 1})

H_{2} O_{2}

25^{0} C ?

2 H_{2} O_{2} (l) \to O_{2} (g) + 2 H_{2} O (l)

Δ H_{f}^{o}

H_{2} O_{2}

H_{2} O

2 H_{2} O_{2} (l) \to 2 H_{2} O (l) + O_{2} (g)

2

27^{o} C

1

Join BYJU'S Learning Program