If 10^x=64 then what is the value of 10^(x^{/2) +1}

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Solution

Given 10^x = 64.

Now

=10^x/2+1

=10^x/2 x 10^1

=(10^x)^1/2 x 10^1

= (64)^1/2 x 10

= 8 x 10
(64^1/2=squareroot(64)=8)

= 80

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