Question

If $a+b:a-b=11:8$, find the value of $a:b$.

Answer 1

Given: $a+b:a-b=11:8$

$\Rightarrow \frac{a+b}{a-b}=\frac{11}{8}$

On cross-multiplying,

$\Rightarrow 8(a+b)=11(a-b)$

$\Rightarrow 8a+8b=11a-11b$

$\Rightarrow 11b+8b=11a-8a$

$\Rightarrow 19b=3a$

$\Rightarrow \frac{a}{b}=\frac{19}{3}$

Hence, the value of $a:b\text{is}19:3$.