wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If 11sin2x+7cos2x=8 then x=______

A
nx±π6,nZ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
nx±π4,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
nx±π3,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
nx±π2,nZ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D nx±π6,nZ
Given 11sin2x+7cos2x=8
11sin2x+77sin2x=8
4sin2x=1
sin2x=14
sin2x=sin2π6
x=nπ±π6,Z

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Trigonometric Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon