Question

If 110 g of salt is present in 550 g of solution, then calculate the concentration of the solution.

Answer 1

A solution comprises two parts i.e.; solute and solvent

• Solute: The component of the solution to be dissolved or the component present in the solution in a lesser quantity.
• Solvent: The component of the solution that dissolves or the component present in the solution in a larger quantity.
• Here, salt or Sodium chloride $\left(\mathrm{NaCl}\right)$ is the solute, and the solvent is not specified.

Step-1: Calculate the mass percentage $(\mathrm{m}/\mathrm{m})$ of the solution

Formula to be used:

$\mathrm{Concentration}\mathrm{in}(\mathrm{m}/\mathrm{m})\%=\frac{\mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{solute}\left(\mathrm{g}\right)}{\mathrm{Mass}\mathrm{of}\mathrm{the}\mathrm{solution}\left(\mathrm{g}\right)}\times 100$

• $\mathrm{m}/\mathrm{m}$ represents mass by mass. It is a way to represent the concentration of the solution.
• It is defined as the mass of the solute in $\mathrm{g}$ dissolved in per $100\mathrm{g}$ of the solution.

Given, Mass of the salt (solute)= $110\mathrm{g}$

Also given, Mass of solution= $550\mathrm{g}$

Substituting the given values in the above formula

• Concentration of the salt solution $(\mathrm{m}/\mathrm{m})\%=\frac{110}{550}\times 100$
• Concentration of the salt solution $(\mathrm{m}/\mathrm{m})\%=\frac{11000}{550}$
• Concentration of the salt solution $(\mathrm{m}/\mathrm{m})\%=20\%(\mathrm{m}/\mathrm{m})$