If 112 = q x 6 + r, then the possible values of r are:

1,2,3,4

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0,1,2,3,4,5

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0,1,2,3

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2,3,5

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Solution

The correct option is B 0,1,2,3,4,5
For the relation $x = q y + r, 0 \leq r \leq y$ [By remainder theorem]
Given, $112 = q x 6 + r$
So, here $r$ lies between $0 \leq r \leq 6$
Hence, the possible values of $r$ is 0,1,2,3,4,5.

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