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Question

If ₹ 12,000 is invested for 112 years at 10% per annum, find the amount received after 112 years.

A
Rs.13,888.5
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B
Rs.14,891.7
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C
Rs.13,891.5
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D
Rs.13,591.8
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Solution

The correct option is C Rs.13,891.5

Here, Principal (P) = ₹ 12000

Rate of interest (R) = 10% per annum
Rate of interest = 5% half yearly
Time (n) = 32 years
= 3 half years.
Amount (A)
=P(1+R100)n=12000(1+5100)3=12000(1+120)3
=12000(2120)3=12000×2120×2120×2120
= ₹ 13,891.50


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