Question

If 13.6 ev energy is required to ionise the hydrogen atom, then the energy required to remove an electron from first exited state (n = 2) is

• A. 10.2 eV
• B. 0 eV
• C. 3.4 eV
• D. 6.8 eV

Answer 1

The correct option is C 3.4 eV

$E_2=-\frac{13.6}{n^2}=-\frac{13.6}{2^2}$
$=-3.4eV$
$E=3.4eV$