If 14 is the HCF of 4p and 21q, then minimum value of p and q is:

p = 7, q = 2

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p = 2, q = 7

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p = 14, q = 3

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None of the above

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Solution

The correct option is A
p = 7, q = 2

Since 14 is HCF of 4p and 21q, then both of them should have 7 and 2 as prime factors.
4p = 2 x 2 x p
21q = 3 x 7 x q
Since 14 is the HCF, p should be 7 and q should be 2.

Suggest Corrections

Similar questions

If 14 is the HCF of 4p and 21q, then minimum value of p and q are:

x^{2} - x - 6 a n d x^{2} + 9 x + 14

cosec A = 4 p + \frac{1}{16 p}

cosec A + cot A

a

b

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a + b

x + 2 p + 3 q = 14

2 x p + 6 p q + 3 q x = 4

x^{2} + 4 p^{2} + 9 q^{2} .

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