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Question

If 14 is the HCF of 4p and 21q, then minimum value of p and q are:


A

1

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B

2

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C

2, x

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D

No common factors exist

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Solution

The correct option is A

1


Since 14 is HCF of 4p and 21q, then both of them should have 7 and 2 as prime factors.
4p = 2 x 2 x p
21q = 3 x 7 x q
Since 14 is the HCF, p should be 7 and q should be 2.


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