If 14 is the HCF of 4p and 21q, then the minimum value of p and q, given p and q are natural numbers are:

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2, x

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No common factors exist

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Solution

The correct option is A
1

Since 14 is HCF of 4p and 21q, thus both of them should have 7 and 2 as prime factors.
4p= 4 x p
21= 3 x 7 x q
Since 14 is the HCF, p should be 7 and q should be 2.

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