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Question

If 15!=2α3β5γ7δ11θ13Φ, then the value of expression αβ+γδ+θΦ is

A
4
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B
6
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C
8
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D
10
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Solution

The correct option is B 6
15!=1×2×3×4×5×6×7×8×9×10×11×12×13×14×15

15!=2×3×22×5×3×2×7×23×32×2×5×11×3×22×13×2×7×3×5

15!=211×36×53×72×11×13

α=11

β=6

γ=3

δ=2

θ=1

Φ=1

αβ+γδ+θΦ=116+32+11=6

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