If 15 cot A = 8, find tan A.

\frac{8}{14}

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\frac{15}{8}

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\frac{17}{8}

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\frac{15}{17}

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Solution

The correct option is B $\frac{15}{8}$
Let us assume a right angled triangle ABC, right angled at B

Given: 15 cot A = 8

So, cot A $= \frac{8}{15}$

$tan A = \frac{1}{cot A} = \frac{15}{8}$

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tan A + 2 tan 2 A + 4 tan 4 A + 8 cot 8 A = k cot A

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Find the value of tan A + 2 tan2A + 4 tan4A + 8 cot 8A

8 tan A = 15

sin A - cos A .

15 \cot A = 8

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