If 15 cot N - 8- find the value of 1-sec2 N-1 is m-15- m is

Given, #160; 15 N = 8 N = 815 1√(^2 N 1) #160;= 1√(tan^2N) (Since, ^2 θ tan^2 θ = 1 )= 1tan N = N = 815 ...

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Applications of Dot Product

If 15 cot N =...

Question

If 15 cot N = 8, find the value of $\frac{1}{\sqrt{s e c^{2} N - 1}}$ is $\frac{m}{15}$ , m is

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\frac{1}{\sqrt{s e c^{2} N - 1}}

m = \sqrt[3]{15}

n = \sqrt[3]{14}

m - n - \frac{1}{m^{2} + m n + n^{2}}

m^{2} cos \frac{2 π}{15} cos \frac{4 π}{15} cos \frac{8 π}{15} cos \frac{14 π}{15} = n^{2}

\frac{m^{2} - n^{2}}{n^{2}}

x : (m^{2} - 2 n) = y : (m^{2} + 2 n)

3 m = 5 x = y = 15

n = 8 \frac{1}{x}

x

(- 10 m^{2} n^{2}) \times (- 20 m n^{15})

m = 1.2

n = - 1

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