Question

If $15\text{g}$ of a molecule contains $3.011\times {10}^{21}$ molecules what will be the molar mass of the molecule?

• A. $300\text{g/mol}$
• B. $3000\text{g/mol}$
• C. $400\text{g/mol}$
• D. $4000\text{g/mol}$

Answer 1

The correct option is B $3000\text{g/mol}$

Given,
The mass of $3.011\times {10}^{21}$ molecules = $15\text{g}$
So, mass of $6.022\times {10}^{23}$ molecules = $\frac{6.022\times {10}^{23}\times 15}{3.011\times {10}^{21}}\text{g}$
$=3000\text{g}$
So, the molar mass of the molecule $3000\text{g/mol}$.