If $(150)^{2}$ is added to the cube of a number, the answer so obtained is 77372. What is the number?

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Solution

The correct option is D
38

Let the number be x.

From the question, $x^{3}$ + $(150^{2})$ = 77372

→ $x^{3}$ + 22500 = 77372

→ $x^{3}$ = 77372 - 22500 = 54872

→ $x = \sqrt[3]{54872} = \sqrt[3]{38 \times 38 \times 38} = 38$

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