If $150 k J$ of energy is needed for a man to walk a distance of $1 k m$ , then how much of glucose one has to consume to walk a distance of $5 k m$ , provided that only $30$ % of the energy available for muscular work. (The enthalpy of combustion glucose is $3000 k J {m o l}^{- 1}$ ).

75 g

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30 g

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180 g

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150 g

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45 g

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Solution

The correct option is B $150 g$
For walking 1 km the man needs 150KJ of energy. To walk 5 kms he needs $150 \times 5 = 750$ KJ energy. If only $30 %$ of energy is available for muscular work, the total energy needed will be $\frac{750}{30} \times 100 = 2500 K J 1$ mole of glucose produces 3000 KJ. Then for producing 2500 KJ, 5/6 mole of glucose = $\frac{5}{6} \times 180 = 150$ gms of glucose will be needed (assuming the molecular weight of glucose=180 gms)

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If 150kJ of energy is needed for a man to walk a distance of 1km, then how much of glucose one has to consume to walk a distance of 5km, provided that only 30% of the energy available for muscular work. (The enthalpy of combustion glucose is 3000kJmol−1).

If $150 k J$ of energy is needed for a man to walk a distance of $1 k m$ , then how much of glucose one has to consume to walk a distance of $5 k m$ , provided that only $30$ % of the energy available for muscular work. (The enthalpy of combustion glucose is $3000 k J {m o l}^{- 1}$ ).