If 15x > 17x then the set of values of x is

{ $x < 0 : x \in N$ }

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{ $x \in Z$ }

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{ $x \in N$ }

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{ $x < 0 : x \in Z$ }

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Solution

The correct option is D
{ $x < 0 : x \in Z$ }

Given, 15x > 17x.

$∵$ 15 < 17, the given case will be only possible for negative values of x.

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