If (16)^2x+3 =(64)^x+3, then 4^2x-2 =

(a) 64

(b) 256

(c) 32

(d) 512

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Solution

We have to find the value ofprovided

So,

Equating the power of exponents we get

The value of is

Hence the correct alternative is

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Similar questions

4^{2 x - 2}

(16)^{2 x + 3} = (64)^{x + 3}

x^{3} - 42 x^{2} + 336 x - 512 = 0

{log}_{2} x + {log}_{2} y \geq 6

x y

x + \frac{1}{x} = 2

x^{3} + \frac{1}{x^{3}} =

(\sqrt[3]{4})^{2 x + \frac{1}{2}} = \frac{1}{32}

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