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Question

If 16 cotA=12, find sinA+cosA÷sinA-cosA

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Solution

16cotA=12

Cot A = 12/16 = 3/4

cosA/sinA = 3/4
let k is a constant

cosA = 3k and sinA = 4k

Put this values in

(sinA+cosA)/(sinA-cosA) = (4k+3k)/(4k-3k)=7k/k=7


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