If 16 cotA=12, find sinA+cosA÷sinA-cosA
16cotA=12
Cot A = 12/16 = 3/4
cosA/sinA = 3/4 let k is a constant
cosA = 3k and sinA = 4k
Put this values in
(sinA+cosA)/(sinA-cosA) = (4k+3k)/(4k-3k)=7k/k=7