If 16 observations are arranged in ascending order, then median is :

8 t h o b s e r v a t i o n

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9 t h o b s e r v a t i o n

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\frac{(8 t h o b s e r v a t i o n + 9 t h o b s e r v a t i o n)}{2}

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\frac{(7 t h o b s e r v a t i o n + 8 t h o b s e r v a t i o n)}{2}

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Solution

The correct option is C $\frac{(8 t h o b s e r v a t i o n + 9 t h o b s e r v a t i o n)}{2}$
For even number of observations median is the mean of $\frac{n}{2}$ th observation and $(\frac{n}{2} + 1)$ th observation:
So, median of 16 observation $= \frac{8 t h o b s e r v a t i o n + 9 t h o b s e r v a t i o n}{2}$

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If 16 observations are arranged in ascending order, then median is :

The correct option is C (8th observation +9th observation)2For even number of observations median is the mean of n2th observation and (n2+1)th observation:So, median of 16 observation =8th observation+9th observation2