If $16 X^{2} - 8 X + 1 = 0$ , then the roots of the equations are_____.

(1 / 4, 1 / 4)

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(1.3 / - 1)

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(2, 3 / 2)

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(2 / 3.1)

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Solution

The correct option is B $(1 / 4, 1 / 4)$
Given equation is
$16 x^{2} - 8 x + 1 - 0$

then
$x = \frac{8 \pm \sqrt{(- 8)^{2} - 4 \times 16}}{2 \times 16}$

$\to x = \frac{8 \pm \sqrt{64 - 64}}{32} \to x = \frac{8}{32} = \frac{1}{4}, \frac{1}{4}$

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