If 17th term of an A.P. exceeds the 13th term by 15 , find common difference.

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Solution

17^th term of A.P t₁₇ = a + 16d.

13^th term of A.P is t₁₃ = a + 12d.

Given that 17th term of an A.P exceeds its 13th term by 15

a + 16d = a + 12d + 15

4d = 15

∴ d = 15/4

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