If $18 g$ of glucose is present in $1000 g$ of solvent, the solution is said to be:

1

molar

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0.1

molar

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0.5

molal

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0.1

molal

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Solution

The correct option is D $0.1$ molal
$G l u c o s e m a s s = 18 g$
Molar mass of glucose $= 180 g / m o l$

$M o l a l i t y = \frac{18}{180} \times \frac{1000}{1000} = \frac{1}{10} = 0.1$ $m o l a l$

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