If 18 C15-218 C16-17 C16-1-n C3- then n-

Given18C15 nbsp;+ 2 (18C16) + nbsp;17C16 nbsp;+ 1 = nbsp;nC3 nbsp; L.H.S nbsp;18C15 nbsp;+ 18C16 nbsp;+ nbsp;18C16 + 17C16 nbsp;+ 1 nbsp; ...

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Common Difference

If 18 C15+218...

Question

If ¹⁸C₁₅ + 2 (¹⁸C₁₆) + ¹⁷C₁₆ + 1 = ⁿC₃, then n = ____________.

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Solution

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^{2 n} C_{3} :

^{n} C_{3} = 11 : 1

n =

^{n - 1} C_{3} +^{n - 1} C_{4} >^{n} C_{3}

Determine n if

(i) (ii)

^{n - 1} C_{3} +^{n - 1} C_{4} >^{n} C_{3},

{2 n_{C}}_{4} : {n_{C}}_{3} = 21 : 1

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