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Question

If a1 (3x2+2x+1) dx=36 ,then the value of a is

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Solution

We have,
a1 (3x2+2x+1) dx=36(3x33+2x22+x]a1=36(x3+x2+x]a1=36(a3+a2+a)(1+1+1)=36a3+a2+a39=0(a3)(a2+4a+13)=0a=3

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