If 1AB + CCA = 697 and there is no carry - over in addition, find the value of A + B + C.

Open in App

Solution

We have, $1 A B + C C A________697$
Since, there is no carry-over in addition,
1 + C = 6
$\Rightarrow$ C = 5
A + C = 9
$\Rightarrow$ A + 5 = 9
$\Rightarrow$ A = 4
and B + A = 7
$\Rightarrow$ B + 4 = 7
$\Rightarrow$ B = 3
Hence, A + B + C = 4 + 3 + 5 = 12

Suggest Corrections

Similar questions

Question 47

If 1AB + CCA = 697 and there is no carry - over in addition, find the value of A + B + C.

\frac{\begin{matrix} 1 & A & B C & C & A \end{matrix}}{697}

1 A B + C C A = 295

B

A = [\begin{matrix} 2 & 3 & 4 - 3 & 4 & 8 \end{matrix}],

B = [\begin{matrix} - 1 & 4 & 7 - 3 & - 2 & 5 \end{matrix}]

A + B = [\begin{matrix} 1 & a & b c & 2 & 13 \end{matrix}],

a + b + c .

If $[\begin{matrix} a + b & 2 5 & a b \end{matrix}] = [\begin{matrix} 6 & 2 5 & 8 \end{matrix}]$ , find the values of a and b.

Join BYJU'S Learning Program