If 1 x -2-1 x -3-1 x -5 are in A-P- Then- x-a 5b 3c 1d 2

Here, we are given three terms, First term (a1) = Second term (a2) = Third term (a3) = We need to find the value of x for which these terms are in A.P. S ...

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Byju's Answer

Standard X

Mathematics

Arithmetic Progression

If 1 x +2,1 x...

Question

If $\frac{1}{x + 2}, \frac{1}{x + 3}, \frac{1}{x + 5}$ are in A.P. Then, x =

(a) 5

(b) 3

(c) 1

(d) 2

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Solution

Here, we are given three terms,

First term (a₁) =

Second term (a₂) =

Third term (a₃) =

We need to find the value of x for which these terms are in A.P. So, in an A.P. the difference of two adjacent terms is always constant. So, we get,

Also,

Now, on equating (1) and (2), we get,

Therefore, for, these three terms will form an A.P.

So, the correct option is (c).

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If 1x+2,1x+3,1x+5 are in A.P. Then, x = (a) 5 (b) 3 (c) 1 (d) 2

If $\frac{1}{x + 2}, \frac{1}{x + 3}, \frac{1}{x + 5}$ are in A.P. Then, x =

(a) 5

(b) 3

(c) 1

(d) 2