If [2 1 3] ⎡⎢⎣−1 0 −1−1 1 00 1 1⎤⎥⎦⎡⎢⎣10−1⎤⎥⎦=A, then find the value of A.
We have, [2 1 3] ⎡⎢⎣−1 0 −1−1 1 00 1 1⎤⎥⎦⎡⎢⎣10−1⎤⎥⎦=A
∴ [2 1 3] ⎡⎢⎣−1 0 −1−1 1 00 1 1⎤⎥⎦=[-2-1+0 0+1+3 -2+0+3]
=[-3 4 1]
Now [-3 4 1]⎡⎢⎣10−1⎤⎥⎦=A
∴A=[−3 4 1]⎡⎢⎣10−1⎤⎥⎦
= [-3+0-1]= [-4]