Question

If $-2.1x+3.1\ge 8.9x-9.8$, then:

• A. $\frac{129}{110}\le x$
• B. $1.17\le x$
• C. $\frac{110}{129}\ge x$
• D. $x\le 1.17$

Answer 1

The correct option is D $x\le 1.17$

Given, $-2.1x+3.1\ge 8.9x-9.8$

By moving $-2.1x$ to the right and $-9.8$ to the left, we get,
$3.1+9.8\ge 8.9x+2.1x$
$12.9\ge 11x$

Transfer 11 to L.H.S
$\frac{12.9}{11}\ge x$
$\frac{129}{110}\ge x$ [$\because$ multiply numerator and denominator by 10]

$1.17\ge x$ which can also be written as $x\le 1.17$
A closed circle at $1.17$ and the red line goes to the left, indicating that $x$ is less than or equal to $\mathrm{1.17.}$


Hence, option (d.) is the correct choice.