If 2.2×10xatm pressure has to be applied to the ends of a steel cylinder to keep its length constant on raising its temperature by 100∘, find the value of x.
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Solution
Variation of length with temperature is given by lt=l0(1+αΔt) or Δll0=αΔt=ε (1) But ε=σE, Thus σ=αΔtE, which is the sought stress of pressure. Putting the value of α and E from Appendix and taking Δt=100∘, we get σ=2.2×103atm