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Question

If 2.2×10xatm pressure has to be applied to the ends of a steel cylinder to keep its length constant on raising its temperature by 100, find the value of x.

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Solution

Variation of length with temperature is given by
lt=l0(1+αΔt) or Δll0=αΔt=ε (1)
But ε=σE,
Thus σ=αΔtE, which is the sought stress of pressure.
Putting the value of α and E from Appendix and taking Δt=100, we get
σ=2.2×103atm

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