If $2.25 \times 10^{20}$ electrons pass through a wire in one minute, find the magnitude of the current flowing through the wire.

0.4 A

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0.6 A

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0.3 A

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0.8 A

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Solution

The correct option is B $0.6 A$
$Q = N e = 2.25 \times 10^{20} \times 1.6 \times 10^{- 19} = 36 C$

$t = 1 m i n = 60 s$

Current= $\frac{Q}{t} = \frac{36}{60}$

$⟹ I = 0.6 A$

Answer-(B)

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If 2.25×1020 electrons pass through a wire in one minute, find the magnitude of the current flowing through the wire.

The correct option is B 0.6 AQ=Ne=2.25×1020×1.6×10−19=36Ct=1min=60sCurrent=Qt=3660⟹I=0.6AAnswer-(B)

If $2.25 \times 10^{20}$ electrons pass through a wire in one minute, find the magnitude of the current flowing through the wire.

The correct option is B $0.6 A$
$Q = N e = 2.25 \times 10^{20} \times 1.6 \times 10^{- 19} = 36 C$

$t = 1 m i n = 60 s$

Current= $\frac{Q}{t} = \frac{36}{60}$

$⟹ I = 0.6 A$

Answer-(B)