Question

If $2^{2x-1}=\frac{1}{8^{x-3}}$, then find the value of '$x$'.

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

The correct option is B $2$

$2^{2x-1}=\frac{1}{8^{x-3}}$
$2^{2x-1}=\frac{1}{8^{x-3}}{2}^{2x-1}\times 8^{x-3}=1[Since{2}^0=1]2^{2x-1}\times {\left(2^3\right)}^{x-3}=2^0\Rightarrow 2x-1+3x-9=0\Rightarrow 5x-10=0\Rightarrow 5x=10\Rightarrow x=2$