1
Question
If (2,3,−1) is the foot of the perpendicular from (4,2,1) to a plane, then the equation of that plane is ax+by+cz=d. Then a+d is
If (2,3,−1) is the foot of the perpendicular from (4,2,1) to a plane, then the equation of that plane is ax+by+cz=d. Then a+d is
Open in App
Solution
The correct option is A 1
Since, the line joining the two points is perpendicular to the plane, it's d.r's will give the normal to the plane.
Direction ratio of the normal =(4−2,2−3,1+1)=(2,−1,2)
Hence, a=2, b=−1, c=2
Since, the plane passes through (2,3,−1),
d=2(2)+3(−1)−1(2)
d=−1
Hence, the required value of the expression is a+d=1.
Since, the line joining the two points is perpendicular to the plane, it's d.r's will give the normal to the plane.
Direction ratio of the normal =(4−2,2−3,1+1)=(2,−1,2)
Hence, a=2, b=−1, c=2
Since, the plane passes through (2,3,−1),
d=2(2)+3(−1)−1(2)
d=−1
Hence, the required value of the expression is a+d=1.
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
