If 2, (3+x) and 8 are in AP, then x = .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2
Given,
2, (3+x) and 8 are in AP.

So, the difference between the consecutive terms must be constant.

$\Rightarrow$ (3+x) - 2 = 8 - (3+x)
$\Rightarrow$ 1+x = 5-x
$\Rightarrow$ 2x = 4
$\Rightarrow$ x = 2

Suggest Corrections

Similar questions

3, x, 11

A P

x =

If $2 x, x + 10, 3 x + 2$ are in AP, then $x =$ ___

log 2

log (2^{x} - 1)

log (2^{x} + 3)

x

1, {log}_{9} (3^{1 - x} + 2), {log}_{3} [{4.3}^{x} - 1]

A P

x

Join BYJU'S Learning Program