If 2+3i is one of the roots of the equation 2x3−9x2+kx−13=0,k∈R, then the real root of this equation :
A
exist and is equal to 12
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B
does not exist
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C
exist and is equal to 1
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D
exist and is equal to −12
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Solution
The correct option is A exist and is equal to 12 Given equation is 2x3−9x2+kx−13=0 where k∈R Since, any odd degree equation with real coefficients has at least one real root. So, real root exist. Let α be the real root. Since, 2+3i is a root of the equation. So, other root will be 2-3i. (Imaginary roots always occurs in conjugate pairs.) Now, sum of roots 2+3i+2−3i+α=92 ⇒α=12