Question

If ∪ = {2, 4, 6, 8, 10, 12, 14, 17} and A = {1, 4, 6, 9, 11, 12}, then set $A^C$​ is

• A. {1, 2, 8, 10, 14, 17}
• B. {2, 8, 10, 14, 17}
• C. {2, 8, 10, 14, 17}
• D. Can't be determined

Answer 1

The correct option is D

Can't be determined

Let ∪ be the universal set and A be a subset of $\cup$. Then the complement of A is the set of all elements of $\cup$ which are not the elements of A.

∴ $A^C$ = $\cup$ - A if A $\subset$ $\cup$

Here A $⊈$ $\cup$

So, $A^C$​ is not defined here

So, (d) is the right option.