Question

If ∪ = {2, 4, 6, 8, 10, 12, 14, 17}, where ∪ is Universal set and some set A = {2, 4, 6, 8, 12} . Find the set $A^C.$

• A. {8, 14, 17}
• B. {8, 10, 17}
• C. {8, 10, 14}
• D. {10, 14, 17}

Answer 1

The correct option is D {10, 14, 17}

Let U be the universal set and A be some set. Then the complement of A, which is denoted by the symbol $A^C$ , is the set of all elements of U which are not the elements of A.

$A^C=U-A$
$A^C=U-A=\{10,14,17\}$
So, (d) is the right option.