Question

If $2.4088\times {10}^{26}$ electrons are there in a pure sample of $H_{2}S{O}_4,$ then find the number of total moles of oxygen present in it.

• A. 32 mol
• B. 4 mol
• C. 8 mol
• D. 16 mol

Answer 1

The correct option is A 32 mol

The number of electrons in one molecule of $H_{2}S{O}_4=1\times 2+16+8\times 4=50$

So, the number of electrons in 1 mole of $H_{2}S{O}_4=50\times 6.022\times {10}^{23}$

Hence $2.0488\times {10}^{26}$ electrons are present in $=\frac{2.4088\times {10}^{26}}{50\times 6.022\times {10}^{23}}\text{mol}{H}_{2}S{O}_4$

$=8\text{mol}{H}_{2}S{O}_4$

Since one mole of $H_{2}S{O}_4$ contains 4 moles of oxygen atoms.
Therefore, 8 moles of $H_{2}S{O}_4$ will contain 32 moles of oxygen atoms.