If $(2 + 6 i) (3 i - 4)$ can be written as $a + b i$ then the value of $a + b$ is

- 8

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8

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- 44

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44

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Solution

The correct option is C $- 44$
We need to find resultant of $(2 + 6 i) (3 i - 4)$
On multiplying, we get
$6 i - 8 + 18 i^{2} - 24 i$
We know $i^{2} = - 1$
So, $- 18 i - 8 - 18$
$= - 26 - 18 i$
$= - (26 + 18 i)$ is the form of $- (a + b i)$
The value of $a + b = - 44$

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Similar questions

If $x^{2} - 8 x + 13$ can be written as (x – a)(x – 6) + 1. Find the value of a.

4^{44} + 4^{44} + 4^{44} + 4^{44} = 4^{x}

x

w = 3 - 2 i

z = - 2 + 4 i

\frac{w}{z}

a + b i

Class interval	$2 - 4$	$4 - 6$	$6 - 8$	$8 - 10$
Frequency	$10$	$2$	$33$	$44$

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