The correct option is A 95 g
The number of electrons in one molecule of MgCl2=(12+(17×2))=46
So, the number of electrons in one mol of MgCl2=46×6.022×1023
Therefore,
46×6.022×1023 electrons are contained in 1 mol of MgCl2
Hence 2.77×1025 electrons will be contained in = 2.77×102546×6.022×1023 mol of MgCl2
= 0.999 mol of MgCl2
Thus, the required mass of MgCl2=(24+2×35.5)×0.999 g
=94.905 g≅95 g