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Question

If (2 , 8) is at an end of a focal chord of the parabola y2 = 32x then the other end of the chord is

A
(32,8)
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B
(32,32)
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C
(2,8)
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D
(32,2)
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Solution

The correct option is B (32,32)
Given,

y2=32x

4a=32

a=8

Now,

(2,8)(at21,2at1)

at21=2

8t21=2

t21=14

8=2(8)t1

t1=12

t2=2

Now,

(at22,2at2)

=8×(2)2,2×8×(2)

=(32,32)

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