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Question

If 2a=3b=6c then

A
c=aba+b
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B
c=a+bab
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C
c=ab2a2+b2
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D
c=ab2a2b2
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Solution

The correct option is A c=aba+b
Let 2a=3b=6c=k
So, 2a=k
k1a=2 .....(i)
Similarly k1b=3 .....(ii)
k1c=6 .....(iii)
Now, we know that 6=2×3
Putting the values of 6, 2 and 3 from (i), (ii) and (iii) we get:
k1c=k1a×k1bk1c=k1a+1b1c=1a+1b1c=b+aabc=aba+b

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