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Question

If -2 and -4 are the zeroes of a quadratic polynomial whose leading coefficient is 2, then find the value of (product of zeroes × coefficient of x).

[Note: In a polynomial, the term containing the highest power of x (i.e. anxn) is the leading term, and we call an the leading coefficient.]

A
96
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B
-96
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C
16
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D
-16
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Solution

The correct option is A 96
Given -2 and -4 are the zeroes of a quadratic polynomial.

So the quadratic polynomial can be written as
f(x)=(x+2)(x+4)
f(x)=x2+6x+8

Now, as the leading coefficient is 2, the quardratic polynomial will be
f(x)=2×(x2+6x+8)
f(x)=2x2+12x+16

So, product of zeroes × coefficient of x
=(2)(4)×12=96

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