Question

If $-2$ and $\frac{7}{2}$ are the zeroes of the polynomial $2x^3-9x^3-19x+42$. The third zero of the polynomial is:

Answer 1

Product of roots $=-\frac{42}{2}=-21\Rightarrow \alpha \times -2\times \frac{7}{2}=-21\Rightarrow \alpha =3$