If 2 begin bmatrix 1 - 3110 - xy - 0 11 - 2end bmatrix - begin bmatrix 586 1188

The correct option is A x=3, y=32 [ 1 amp;3; 0 amp;x ]+[ y amp;0; 1 amp;2 ]=[ 5 amp;6; 1 amp;8 ] ⇒[ 2+y amp;6; 1 amp;2x+ ...

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Byju's Answer

Standard XII

Mathematics

Consistency of Linear System of Equations

if 2 begin bm...

Question

if $2 [\begin{matrix} 1 & 3 0 & x \end{matrix}] + [\begin{matrix} y & 0 1 & 2 \end{matrix}] = [\begin{matrix} 5 & 6 1 & 8 \end{matrix}]$ , then the value of $x$ and $y$ are

x = 3, y = 3

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x = 3, y = 3

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x = 3, y = 3

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x = - 3, y = - 3

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Solution

The correct option is A $x = 3, y = 3$
$2 [\begin{matrix} 1 & 3 0 & x \end{matrix}] + [\begin{matrix} y & 0 1 & 2 \end{matrix}] = [\begin{matrix} 5 & 6 1 & 8 \end{matrix}]$
$\Rightarrow [\begin{matrix} 2 + y & 6 1 & 2 x + 2 \end{matrix}] = [\begin{matrix} 5 & 6 1 & 8 \end{matrix}]$
$\Rightarrow y = 3, x = 3$

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Similar questions

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Q. Let

A = ⎡ ⎢ ⎣ \begin{matrix} - 3 & 0 & 2 1 & x & 5 - 2 & 0 & x^{2} \end{matrix} ⎤ ⎥ ⎦, B = ⎡ ⎢ ⎣ \begin{matrix} 2 b - 1 \end{matrix} ⎤ ⎥ ⎦

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if 2[130x]+[y012]=[5618], then the value of x and y are

The correct option is A x=3,y=32[130x]+[y012]=[5618] ⇒[2+y612x+2]=[5618] ⇒y=3,x=3

if $2 [\begin{matrix} 1 & 3 0 & x \end{matrix}] + [\begin{matrix} y & 0 1 & 2 \end{matrix}] = [\begin{matrix} 5 & 6 1 & 8 \end{matrix}]$ , then the value of $x$ and $y$ are