If 2 boys and 2 girls are to be arranged in a row so that the girls are not next to each other, how many possible arrangements are there?

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Solution

The correct option is C 12
Total possible arrangement =4!=24
Total possible arrangements that two girls sit together= $3! \times 2! = 12$
So, required arrangement=24-12=12

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If 2 boys and 2 girls are to be arranged in a row so that the girls are not next to each other, how many possible arrangements are there?

The correct option is C 12Total possible arrangement =4!=24 Total possible arrangements that two girls sit together=3!×2!=12 So, required arrangement=24-12=12

The correct option is C 12
Total possible arrangement =4!=24
Total possible arrangements that two girls sit together= $3! \times 2! = 12$
So, required arrangement=24-12=12