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Question

If 2cosθ=x=1xand2cosϕ=y+1y etc., then prove that :
xy+yx=2cos(θϕ)

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Solution

xy=eiθeiθ=ei(θϕ)
y/x=(x/y)1=ei(θϕ)
xy+yx=2cos(θϕ).

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