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Numbers in General Form

If 2 divides ...

Question

If 2 divides $x^{2} + 6 x + 9$ then $x + 3$ would be a/an
for any value of $x$ ,
provided $x^{2} + 6 x + 9$ is a positive integer.

A

odd number

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B

even number

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C

prime number

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Solution

The correct option is B even number

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Similar questions

f (x) = \sqrt{x^{2} + 6 x + 9} - \sqrt{x^{2} - 6 x + 9}

, then the value of

f (\frac{456}{123}) - f (- \frac{456}{123})

x \in R - {3},

then the possible value(s) of the expression

\frac{\sqrt{x^{2} - 6 x + 9}}{3 - x} + 2

\frac{p}{q} = \frac{x + 3}{x - 3^{'}}

then what is the value of

\frac{p^{2} + q^{2}}{p^{2} - q^{2}} ?

A = \int \frac{d x}{x^{2} + 6 x + 25}

B = \int \frac{d x}{x^{2} - 6 x - 27}

12 (A + B) = λ . {tan}^{- 1} (\frac{x + 3}{4}) + μ . ln ∣ ∣ ∣ \frac{x - 9}{x + 3} ∣ ∣ ∣ + C

, then the value of

(λ + μ)

\dots

.

f (x) = \sqrt{x^{2} + 6 x + 9} - \sqrt{x^{2} - 6 x + 9}

, then the value of

f (\frac{456}{123}) - f (- \frac{456}{123})

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