You visited us 1 times! Enjoying our articles? Unlock Full Access!

Location of Roots

If 2-i is o...

Question

If $2 - i$ is one root of the equation $a x^{2} - b x + c = 0$ , and $a, b, c$ are rational numbers, then the other root is

- i - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

i - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 + i

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 i + i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2 + i$
Fact: If coefficient of a quadratic equation are rational number, then complex root occur in conjugate pair.

Thus if one root of $a x^{2} - b x + c = 0$ is $2 - i$ , then other root must be $2 + i$

Suggest Corrections

Similar questions

i x^{2} - 2 (i + 1) x + (2 - i) = 0

2 - i

\frac{1}{2 - i}

a x^{2} + b x + c = 0

i = \sqrt{- 1}

\frac{1}{3 - 2 \sqrt{2}}

p x^{2} + d x + q = 0

\sqrt{5} - i \sqrt{7}

a x^{4} + b x^{3} + c x^{2} + d x + e = 0

a, b, c, d, e

x^{3} - 5 x^{2} + 9 x - 5 = 0

a x^{2} + b x + c = 0; (a, b, c \in R)

2 x^{2} + 3 x + 4 = 0

a : b : c = 2 : 3 : 4

p + i q

p - i q

p, q \in R, i = \sqrt{- 1}

Join BYJU'S Learning Program